1/m-2/8/m^2-4

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Solution for 1/m-2/8/m^2-4 equation:


D( m )

m^2 = 0

m = 0

m^2 = 0

m^2 = 0

1*m^2 = 0 // : 1

m^2 = 0

m = 0

m = 0

m = 0

m in (-oo:0) U (0:+oo)

1/m-((2/8)/(m^2))-4 = 0

1/m+(-1/4)*m^-2-4 = 0

m^-1-1/4*m^-2-4 = 0

t_1 = m^-1

1*t_1^1-1/4*t_1^2-4 = 0

t_1-1/4*t_1^2-4 = 0

DELTA = 1^2-(-4*(-1/4)*4)

DELTA = -3

DELTA < 0

m belongs to the empty set

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